VVI MCQs Practice Set - 4 : Collection of Past MCQs of BSc Ag/Hrt, IAAS, TU

These Questions are Real Questions of BSc Ag/BVSc & AH, AFU. Practice it and Try to solve these all. Best of Luck. Solutions are available below after questions.

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Questions:-

1. I am fed up with his behavior at school. Here ‘fed up with’ denotes
a. noticeable 8. Capillarity is
a. property of liquid by virtue of which it produces dragging force8. B
Property of liquid by virtue of which it produces dragging force is viscosity, Rising or falling of liquid in a tube is capillarity. Liquid tends to occupy minimum surface area.
Capillarity is a physical phenomenon in which liquids flow without the help of gravity. Liquid even rise to a height against gravity, through narrow tubes. Capillary action is due to the phenomenon of surface tension of liquid as well as adhesive forces between liquid molecules and molecules of the narrow tube.
The rise and fall of liquid in a capillary tube is called capillarity.
Some applications of capillarity are:
a. Towels soak water on account of capillarity.
b. Oil rises in the long narrow spaces between the threads of the wick as they act as a capillary.Acceleration due to gravity at a height h above the surface g′ = g (1 − 2h/R)
This suggest that acceleration due to gravity decreases as we go up higher above the earth surface.
At the surface, we have h=0
Thus acceleration due to gravity at the surface g′=g (maximum).
Also acceleration due to gravity is zero at the centre of earth.
Thus acceleration due to gravity is maximum at the earth's surface.Resistance of metallic wire: R
When cut into 10 equal parts, each part will have resistance = R / 10​
When two pieces are joined in series, then R′ = R/10 + R/10 = R/5
Now each such combinations are joined in parallel then
1/R′′ = 1 / (R/5) ​+  1 / (R/5) + 1 / (R/5) + 1 / (R/5) + 1 / (R/5) =  5 / (R/5) = 25 / R
⇒R′′ = R / 25 ​ΩWhen an object is placed beyond the centre of curvature then a ray of light AO which is parallel to the principal axis, pass through the focus F along the direction OF after refraction. While the other ray AC pass through the optical centre C and goes straight without any deviation according to the rule (2). These two refracted light rays intersect each other at point A’, between the focus F and centre of curvature 2F on the other side of the lens. In this way, a diminished, real and inverted image A’B’ is formed.
12. A
A particle representing a quantum of light or other electromagnetic radiation. A photon carries energy proportional to the radiation frequency but has zero rest mass.
Giardia is a parasite responsible for the diarrheal disease known as giardiasis. In it, four pair means 8 flagella which are arranged as four lateral, two ventral, and two caudal. The organism which is composed of 11 microtubules including two core microtubules.
Giardia is a genus of anaerobic flagellated protozoan parasites of the phylum metamonada that colonise and reproduce in the small intestines of several vertebrates, causing giardiasis. Their life cycle alternates between a swimming trophozoite and an infective, resistant cyst.15. A
Cockroaches are mainly nocturnal and will run away when exposed to light.
Also, cockroaches are omnivorous, with the exception of the wood-eating species such as Cryptocercus.Sinus venosus is a triangular chamber attached dorsally to heart formed by the union of three main vena cava. They are the two precavals and one post caval. Insects are arthropods having compound eyes and three pairs of legs. Arthropoda is the largest phylum. Animals belonging to this phylum consists exoskeleton segmented body with jointed legs and compound eyes. Egg laying mammals are primitive mammals which lay eggs like reptiles and belongs to the Monotreme. These animals are restricted to Australian region.The nucleolus is formed by the secondary constriction. The nucleolus is the largest structure present in the nucleus of eukaryotic cells where it primarily serves as the site of ribosome synthesis and assembly. Nucleoli also have other important functions like the assembly of signal recognition particles and playing a role in the cell's response to stress. Nucleoli are made of proteins and RNA and form around specific chromosomal regions.Yeast from brewing industry is harvested and used as a food It is rich in protein and vitamin-B (Riboflavin).21. D
Placentation refers to the formation, type and structure or arrangement of the placenta. It is the attachment of ovules inside the ovary. Basal placentation is found in monocarpellary to a multicarpellary, syncarpous ovary, usually, a single ovule is attached at the base. In Asteraceae, the ovary is bicarpellary syncarpous ovary with single ovule and basal placentation is seen. In Poaceae, the ovary is monocarpellary, superior ovary with single ovule and basal placentation is seen. Biological community is the assemblage of interdependent and interacting populations of different species present in an area.An ionic compound is composed of cation and anion and by the electrostatic force of attraction. But after formation, cation attracts the electron pair towards itself and cause some deformation of electron density of anion.
Above all if the ionic character predominates over covalent character, then we call it ionic.
NaH consists of Na+ cations and H− anions. The bond is purely ionic and the compound is ionic.BOD or Biochemical Oxygen Demand measures the degree of impurity of a water body or sample due to organic matter. BOD is the amount of dissolved oxygen needed by aerobic microbes to breakdown the organic matter present in the water body.
So, the correct answer is extend of pollution with organic matter.25. C
The seven molecules of water attached to MgSO4​.7H2​O are known as water of hydration. By definition, it is the amount of water attached to a compound to form a hydrate. Epsom salt is also known as Magnesium sulphate heptahydrate.If the numbers a, b and c are in AP, then
b-a=c-b
⇒2b=a+c
The given three numbers (2p-1),(3p+1) and 11 are in AP.
Then,
2(3p+1)=(2p−1)+11
⇒6p+2=2p−1+11
⇒6p+2=2p+10
⇒6p−2p=10−2
⇒4p=8
⇒p=8/4
⇒p=2
We have total of 8 points here. The number of points we need to make a triangle is 3. We can select 3 non-collinear points out of 8 points in 8C3 way. We can deduct the collinear points in 5C3 ways
Therefore, the number of triangles formed out of 8 points removing the possibility of selecting collinear points = 8C3 – 5C3 – 1